If the temperature of black body is increased by a
factor of 2, the amount of energy and volume radiated increases by a factor of
. . . . . . . . . .
( a ) 2 (
b ) 4 ( c ) 8 ( d ) 16
Definition
A black body is a theoretical object that absorbs all
radiation that incident on its surface. As there is no reflection of light at
room temperature the body is appears black ( that’s why it is called as black
body ). Interestingly, when heated a ‘black body’ can radiate depending upon
the temperature to which it is heated. This is known as ‘black body radiation’.
According to Stefan the
power radiated from the blackbody can be determine by the formula
P = σ A T4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ( 1 )
Where
P = Power
radiated from the black body in W ( J / s )
σ = Stefan's Constant
5.67 x 10 - 8 W m - 2 K - 4 .
A = Surface area of
black body ( m ² )
T = Temperature
of body ( in Kelvin Scale [ K ] )
In other words we can
say that the power radiated by the body is varies linearly with the forth power
of its absolute temperature ( T 4 ) . Therefore the total
energy increases so much for a relatively small increase in temperature.
Stefan's Law ( P = σ A T4 ) |
Problem:
If the
temperature of black body is increased by a factor of 2, the amount of energy
and volume radiated increases by a factor of . . . . . . . . . .
Solution :
Let us consider that
the P1 be the power radiated from the black body in W ( J / s )
at initial temperature T1 ( K
). ‘ A ’ be the
Surface area of black body
and P2 be the power
radiated from the black body in W ( J / s ) at final temperature
T2 ( K ) .
At initial temperature T1 the Stefan’s law can be written
as
P1 = σ A T14 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . ( 2 )
Similarly at final
temperature T2 the Stefan’s
law can be written as
P2 = σ A T24 . . . . . . . .. . . . . . . . . . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ( 3 )
Taking ratio of eqn
( 2 ) and ( 3 ) we get
( P 1 / P 2 ) = [ ( σ A
T14 ) / ( σ A T24 ) ] . . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ( 4 )
But
2 T1 = T2
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . . . . . . ( Given )
Putting this value in
equation ( 4 ) we get ,
( P 1 / P 2
) = { [ σ A T14 ] / [ σ A ( 2 T1)4 ]
} . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .( 5 )
( P 1 / P 2
) = ( 1 / 16 )
P
2 = 16
P1 . . . . . . . . . . . . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ( Answer )
Therefore we can say
that if If the temperature of black body is increased by a factor of 2, the amount
of energy and volume radiated increases by a factor of 16 (Answer
: d)
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