Friday, August 5, 2016

A planet of mass m moves in the inverse square central force field of the Sun of mass M . If the semi-major and semi-minor axes of the orbit are a and b , respectively, the total energy of the planet is:

          (a)    - ( G M m ) / ( a + b )
          (b)   - ( G M m ) [ ( 1 / a ) + ( 1 / b ) ]
          (c)    – [ ( G M m ) / a ] [ ( 1 / b ) - ( 1 / a ) ]
          (d)   - ( G M m ) / [ ( a – b ) / ( a + b )]

Saturday, May 7, 2016

Three particles, each having a charge of 10 µC are placed at corners of an equilateral triangle of side 10 cm. The electrostatic potential energy of system is ? ( Given 1/4πεo = 9 X 109 N-m2C2) (MHT-CET ~ 2011)

Three particles, each having a charge of 10 µC are placed at corners of an equilateral triangle of side 10 cm. The electrostatic potential energy of system is ? ( Given   = 9 X 109 N-m2C2) (MHT-CET ~ 2011)

a ] zero                                 b] Infinity                            c] 27 J                    d] 100 J

Saturday, April 30, 2016

Two charges of equal magnitude q are placed in air at a distance 2 a apart and third charge -2q is placed at mid – point. The potential energy of a system is? ( ԑo = permittivity of free space ) . (MHT-CET ~ 2014)

Two charges of equal magnitude q are placed in air at a distance 2 a apart and third charge -2q is placed at mid – point. The potential energy of a system is? ( ԑo = permittivity of free space ) . (MHT-CET ~ 2014)

a ] - q 2 / ( 8 π ε o a )                        b] - 3 q 2 / ( 8 π ε o a )                     
c] – 5 q 2 / ( 8 π ε o a )                     d] - 7 q 2 / ( 8 π ε o a )

Sunday, April 24, 2016

Two concentric sphere kept in air have radii R & r . they have similar change and equal charge density σ. The electric potential at their common centre is? ( MHT - CET ~ 2014 )

Two concentric sphere kept in air have radii R & r . they have similar change and equal charge density σ. The electric potential at their common centre is? ( MHT - CET ~ 2014 )
a ]  σ ( R + r ) / ε o            b ] σ ( R – r ) / ε o
c ] σ ( R + r ) / 2 ε o               d ] σ ( R + r ) / 4 ε o