Two charges of equal magnitude q are placed in air at a distance 2
a apart and third charge -2q is placed at mid – point. The potential energy of
a system is? ( ԑo = permittivity of free space ) . (MHT-CET ~
2014)
a ] - q 2 / ( 8 π ε o
a ) b] - 3 q
2 / ( 8 π ε
o a )
c] – 5 q 2 / ( 8 π ε o
a ) d]
- 7 q 2 / ( 8 π ε o a )
Solution :
Electric Potential Energy :
The electric potential energy of system of system of point charges
can be define as the work required to assemble the system of charges by
bringing them from infinite distance to their present location.
U =(1/ 4 π ε
o ) { [ ( q 1 q 2 ) / r 1 2 ] + [ ( q 1 q 3
) / r 1 3 ] + [ ( q 2
q 3 ) / r 2 3 ] }
The Electric potential energy of system can be given as
U =(1 / 4 π ε
o ) { [ ( q 1 q 2 ) / r 1 2 ] + [ ( q 1 q 3
) / r 1 3 ] + [ ( q 2
q 3 ) / r 2 3 ] }
U = U =(1/ 4 π ε
o ) { [ ( q 1 (-2q 1 ) / a ] + [ ( q 1 (-2q 1
) / a ] + [ ( q 1 q 1 )
/ 2a ] }
U =(1/ 4 π ε
o ) { - [ (2q 2 )
/ a ] - [ (2q 2 ) / a ] + [ ( q 2
) / 2 a ] }
U =( 1/ 4 π ε o
) {
- [ (4q 2 ) ) / a ] - [ (q 2 )
) / 2a ]}
U =( - 7 q 2/ 8 π
ε o
a )
The potential energy of system is given
by U =( - 7 q 2/ 8 π ε o
a )
The correct option is : option [ d ]
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