A
Closely wound flat circular coil of 50 turns wound flat circular coil of 50
turns has a diameter of 10 cm carries a current of 4 ampere. Determine the
magnetic induction at center of coil.
Solution:
Given:
No.
of turns : n = 50
Diameter
of coil : d = 10
cm = 0.1 m
Current
through coil : I = 4 A
The
magnetic induction at center of current carrying coil can be given as
B = ( μo n I ) / ( 2 r )
Where,
r is the radius of coil
B = ( μo n I ) / d
Putting
values we get,
B = ( 4 π X 10-7 X 50 X 4 )
B = 2.513 10-4 T
The
magnetic induction at a center of coil of 50 turns and 10 cm diameter carrying
a current of 4 ampere is
B
= 2.513 10-4 T
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