The
displacement of an oscillating particle is given by x = a sin ( ω t ) + b cos (
ω t ), where a and b are constant show that the motion of particle is S. H. M.
Solution:
S . H . M . ( Simple Harmonic Motion )
Definition:
S. H. M. can be defined as the periodic motion of body in which the restoring force ( or
acceleration) is directed towards the mean position and its magnitude is
directly proportional to the displacement from mean position.
The displacement of particle
is given by
x = a sin ( ω t ) + b cos ( ω
t )
- - - - - - - - - ( 1 )
We know that the velocity is
rate if change of displacement.
Therefore,
v = dx / dt
v = dx / dt
v = d / dt ( a sin ω t + b
cos ω t)
v = a ω cos ω t - b ω sin ω t
v = a ω cos ω t - b ω sin ω t
But acceleration is rate of
change if velocity, the above equation can be written as
a = dv / dt
a = d / dt ( a ω cos ω t - b ω sin ω t )
a = - a ω 2 sin ω t + b ω 2 cos ω t
a = - ω 2 [ a sin ω t + b cos ω t ]
a = dv / dt
a = d / dt ( a ω cos ω t - b ω sin ω t )
a = - a ω 2 sin ω t + b ω 2 cos ω t
a = - ω 2 [ a sin ω t + b cos ω t ]
From equation ( 1 )
a= - ω 2 x
as ω 2 is constant
a= - ω 2 x
as ω 2 is constant
a α - x
Since acceleration is
directly proportional to the displacement, the motion of particle is S. H. M.
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