An object is placed at a distance of 6 cm from a convex mirror. If the focal length of a mirror is 12 cm find the position and nature of an image.
Given:
Distance of object = u = -6 cm (the -ve sign represents the object is placed at left side of the mirror.)
Focal length of mirror = f = 12 cm
Solution:-
using mirror equation we get
( 1 / f ) = ( 1 / u ) + ( 1 / v )
therefore,
( 1/ v ) = (1 / f ) - ( 1 / u )
( 1/ v ) = (1 / 12 ) - ( 1 / - 6 )
( 1/ v ) = (1 / 12 ) + ( 1 / 6 )
( 1/ v ) = (1 / 12) + { ( 2 / 2) ( 1 / 6 ) }
( 1/ v ) = (1 / 12 ) + ( 2 / 12)
( 1/ v ) = (1 +2)/ 12
( 1/ v ) = 3 / 12
( 1 / v ) = (1 / 4 )
i.e.
v = 4 cm
In case of convex mirror, the image is always virtual, erect and diminished.....
Given:
Distance of object = u = -6 cm (the -ve sign represents the object is placed at left side of the mirror.)
Focal length of mirror = f = 12 cm
Solution:-
using mirror equation we get
( 1 / f ) = ( 1 / u ) + ( 1 / v )
therefore,
( 1/ v ) = (1 / f ) - ( 1 / u )
( 1/ v ) = (1 / 12 ) - ( 1 / - 6 )
( 1/ v ) = (1 / 12 ) + ( 1 / 6 )
( 1/ v ) = (1 / 12) + { ( 2 / 2) ( 1 / 6 ) }
( 1/ v ) = (1 / 12 ) + ( 2 / 12)
( 1/ v ) = (1 +2)/ 12
( 1/ v ) = 3 / 12
( 1 / v ) = (1 / 4 )
i.e.
v = 4 cm
In case of convex mirror, the image is always virtual, erect and diminished.....
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